Nuprl - Proof: eqof eq btrue 1

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At: eqof eq btrue 1

1. A : Type
2. eq : A

x,y:A. x = y

eq(x,y)
4. i : A
5. i = i

eq(i,i)

(eq(i,i)) ~ true

By:	AutoBoolCase (eq(i,i)) THEN Analyze -1 THEN BackThruSomeHyp

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html