IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html
At:
double sum difference1111 1. n : 2. m : 3. f : nm 4. g : nm 5. d : 6. sum(sum(f(x,y)-g(x,y) | y < m) | x < n) = d 7. i : n sum(f(i,y) | y < m)-sum(g(i,y) | y < m) = sum(f(i,y)-g(i,y) | y < m)
By:
Assert (sum(f(i,y) | y < m) = sum(g(i,y) | y < m)+sum(f(i,y)-g(i,y) | y < m))