Nuprl Lemma : power-vs-sq

[K,S:Top].  (K^S Point= S ⟶ |K| zero= λs.0 a+b= λs.((a s) +K (b s)) a*b= λs.(a (b s)))


Proof




Definitions occuring in Statement :  power-vs: K^S mk-vs: mk-vs uall: [x:A]. B[x] top: Top infix_ap: y apply: a lambda: λx.A[x] function: x:A ⟶ B[x] sqequal: t rng_times: * rng_zero: 0 rng_plus: +r rng_car: |r|
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T power-vs: K^S vs-exp: V^S vs-sum: Σs:S. V[s] one-dim-vs: one-dim-vs(K) vs-point: Point(vs) mk-vs: mk-vs all: x:A. B[x] top: Top eq_atom: =a y ifthenelse: if then else fi  bfalse: ff btrue: tt vs-0: 0 vs-add: y vs-mul: x
Lemmas referenced :  rec_select_update_lemma top_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut sqequalRule extract_by_obid sqequalHypSubstitution dependent_functionElimination thin isect_memberEquality voidElimination voidEquality hypothesis sqequalAxiom isectElimination hypothesisEquality because_Cache

Latex:
\mforall{}[K,S:Top].    (K\^{}S  \msim{}  Point=  S  {}\mrightarrow{}  |K|  zero=  \mlambda{}s.0  a+b=  \mlambda{}s.((a  s)  +K  (b  s))  a*b=  \mlambda{}s.(a  *  (b  s)))



Date html generated: 2018_05_22-PM-09_42_41
Last ObjectModification: 2017_11_09-PM-01_42_29

Theory : linear!algebra


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