Nuprl Lemma : and_comm

[A,B:ℙ].  (A ∧ ⇐⇒ B ∧ A)


Proof




Definitions occuring in Statement :  uall: [x:A]. B[x] prop: iff: ⇐⇒ Q and: P ∧ Q
Definitions unfolded in proof :  uall: [x:A]. B[x] iff: ⇐⇒ Q and: P ∧ Q implies:  Q member: t ∈ T prop: rev_implies:  Q
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity Error :isect_memberFormation_alt,  independent_pairFormation lambdaFormation sqequalHypSubstitution productElimination thin hypothesis productEquality cumulativity hypothesisEquality Error :inhabitedIsType,  Error :universeIsType,  universeEquality

Latex:
\mforall{}[A,B:\mBbbP{}].    (A  \mwedge{}  B  \mLeftarrow{}{}\mRightarrow{}  B  \mwedge{}  A)



Date html generated: 2019_06_20-AM-11_15_57
Last ObjectModification: 2018_09_26-AM-10_23_54

Theory : core_2


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