Nuprl Lemma : base-respects-equality

[T:Type]. respects-equality(Base;T)


Proof




Definitions occuring in Statement :  respects-equality: respects-equality(S;T) uall: [x:A]. B[x] base: Base universe: Type
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T respects-equality: respects-equality(S;T) all: x:A. B[x] implies:  Q prop:
Lemmas referenced :  trivial-equal equal-wf-base istype-base
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity Error :isect_memberFormation_alt,  introduction cut Error :lambdaFormation_alt,  hypothesis thin extract_by_obid sqequalHypSubstitution isectElimination hypothesisEquality equalitySymmetry hyp_replacement applyLambdaEquality sqequalRule because_Cache Error :equalityIsType4,  Error :universeIsType,  Error :inhabitedIsType,  Error :lambdaEquality_alt,  dependent_functionElimination axiomEquality Error :functionIsTypeImplies,  universeEquality

Latex:
\mforall{}[T:Type].  respects-equality(Base;T)



Date html generated: 2019_06_20-AM-11_13_40
Last ObjectModification: 2018_11_21-AM-10_44_05

Theory : core_2


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