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Step * 2 1 1 of Lemma divides-iff-gcd-assoced

.....assertion..... 
1. x : ℤ
2. y : ℤ
3. gcd(x;y) | x
4. x | gcd(x;y)
⊢ gcd(x;y) | y
BY
{ (BLemma `gcd_is_divisor_2` THEN Auto) }

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Latex:

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Latex:
.....assertion..... 
1.  x  :  \mBbbZ{}
2.  y  :  \mBbbZ{}
3.  gcd(x;y)  |  x
4.  x  |  gcd(x;y)
\mvdash{}  gcd(x;y)  |  y


By

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Latex:
(BLemma  `gcd\_is\_divisor\_2`  THEN  Auto)

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