Step
*
1
1
of Lemma
can-find-first2
.....subterm..... T:t
1:n
1. T : Type
2. L : T List
3. P : {x:T| (x ∈ L)} ⟶ 𝔹
4. x : ∃x:{x:T| (x ∈ L)} [first-member({x:T| (x ∈ L)} ;x;L;P)]
⊢ x ∈ ∃x:T [first-member(T;x;L;P)]
BY
{ ((D (-1) THEN D -2) THEN MemTypeCD) }
1
1. T : Type
2. L : T List
3. P : {x:T| (x ∈ L)} ⟶ 𝔹
4. x : T
5. (x ∈ L)
6. first-member({x:T| (x ∈ L)} ;x;L;P)
⊢ x ∈ T
2
.....set predicate.....
1. T : Type
2. L : T List
3. P : {x:T| (x ∈ L)} ⟶ 𝔹
4. x : T
5. (x ∈ L)
6. first-member({x:T| (x ∈ L)} ;x;L;P)
⊢ first-member(T;x;L;P)
3
.....wf.....
1. T : Type
2. L : T List
3. P : {x:T| (x ∈ L)} ⟶ 𝔹
4. x : T
5. (x ∈ L)
6. first-member({x:T| (x ∈ L)} ;x;L;P)
7. x1 : T
⊢ first-member(T;x1;L;P) ∈ Type
Latex:
Latex:
.....subterm..... T:t
1:n
1. T : Type
2. L : T List
3. P : \{x:T| (x \mmember{} L)\} {}\mrightarrow{} \mBbbB{}
4. x : \mexists{}x:\{x:T| (x \mmember{} L)\} [first-member(\{x:T| (x \mmember{} L)\} ;x;L;P)]
\mvdash{} x \mmember{} \mexists{}x:T [first-member(T;x;L;P)]
By
Latex:
((D (-1) THEN D -2) THEN MemTypeCD)
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