Step
*
1
1
of Lemma
decidable__q-constraints
1. k : ℕ
2. ∀k1:ℕk. ∀A:(ℕ ⟶ ℚ × ℤ) List. Dec(∃y:ℚ List [q-constraints(k1;A;y)])
3. k = 0 ∈ ℤ
⊢ ∀A:(ℕ ⟶ ℚ × ℤ) List. Dec(∃y:ℚ List [q-constraints(0;A;y)])
BY
{ (RepUR ``q-constraints`` 0 THEN RWO "q-linear-base" 0 THEN Auto) }
1
.....decidable?.....
1. k : ℕ
2. ∀k1:ℕk. ∀A:(ℕ ⟶ ℚ × ℤ) List. Dec(∃y:ℚ List [q-constraints(k1;A;y)])
3. k = 0 ∈ ℤ
4. A : (ℕ ⟶ ℚ × ℤ) List
⊢ Dec(∃y:ℚ List [((||y|| = 0 ∈ ℤ) c∧ (∀xr∈A.q-rel(snd(xr);(fst(xr)) 0)))])
Latex:
Latex:
1. k : \mBbbN{}
2. \mforall{}k1:\mBbbN{}k. \mforall{}A:(\mBbbN{} {}\mrightarrow{} \mBbbQ{} \mtimes{} \mBbbZ{}) List. Dec(\mexists{}y:\mBbbQ{} List [q-constraints(k1;A;y)])
3. k = 0
\mvdash{} \mforall{}A:(\mBbbN{} {}\mrightarrow{} \mBbbQ{} \mtimes{} \mBbbZ{}) List. Dec(\mexists{}y:\mBbbQ{} List [q-constraints(0;A;y)])
By
Latex:
(RepUR ``q-constraints`` 0 THEN RWO "q-linear-base" 0 THEN Auto)
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