Nuprl Lemma : rbinop_wf

[op:ℤ]. ∀[p,q:ℝ].  rbinop(op;p;q) ∈ ℝ supposing ((op 6 ∈ ℤ q ≠ r0) ∧ ((op 10 ∈ ℤ (r0 < p))


Proof




Definitions occuring in Statement :  rbinop: rbinop(op;p;q) rneq: x ≠ y rless: x < y int-to-real: r(n) real: uimplies: supposing a uall: [x:A]. B[x] implies:  Q and: P ∧ Q member: t ∈ T natural_number: $n int: equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a rbinop: rbinop(op;p;q) and: P ∧ Q false: False implies:  Q not: ¬A prop: subtype_rel: A ⊆B
Lemmas referenced :  rsub_wf rmul_wf rdiv_wf rmax_wf rmin_wf radd_wf realexp_wf rless_wf int-to-real_wf equal-wf-base int_subtype_base rneq_wf real_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut sqequalRule sqequalHypSubstitution productElimination thin int_eqEquality hypothesisEquality natural_numberEquality extract_by_obid isectElimination hypothesis because_Cache independent_isectElimination independent_functionElimination dependent_set_memberEquality axiomEquality equalityTransitivity equalitySymmetry productEquality functionEquality intEquality applyEquality baseClosed isect_memberEquality

Latex:
\mforall{}[op:\mBbbZ{}].  \mforall{}[p,q:\mBbbR{}].    rbinop(op;p;q)  \mmember{}  \mBbbR{}  supposing  ((op  =  6)  {}\mRightarrow{}  q  \mneq{}  r0)  \mwedge{}  ((op  =  10)  {}\mRightarrow{}  (r0  <  p))



Date html generated: 2017_10_04-PM-11_01_42
Last ObjectModification: 2017_07_28-AM-08_53_39

Theory : reals_2


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