Nuprl Lemma : pair_support_double_sum

∀[n,m:ℕ]. ∀[f:ℕn ⟶ ℕm ⟶ ℤ]. ∀[x1,x2:ℕn]. ∀[y1,y2:ℕm].
  (sum(f[x;y] | x < n; y < m) = (f[x1;y1] + f[x2;y2]) ∈ ℤ) supposing 
     ((∀x:ℕn. ∀y:ℕm.  ((¬((x = x1 ∈ ℤ) ∧ (y = y1 ∈ ℤ))) ⇒ (¬((x = x2 ∈ ℤ) ∧ (y = y2 ∈ ℤ))) ⇒ (f[x;y] = 0 ∈ ℤ))) and 
     ((¬(x1 = x2 ∈ ℤ)) ∨ (¬(y1 = y2 ∈ ℤ))))


Proof




Definitions occuring in Statement :  double_sum: sum(f[x; y] | x < n; y < m),  int_seg: {i..j-},  nat: ℕ,  uimplies: b supposing a,  uall: ∀[x:A]. B[x],  so_apply: x[s1;s2],  all: ∀x:A. B[x],  not: ¬A,  implies: P ⇒ Q,  or: P ∨ Q,  and: P ∧ Q,  function: x:A ⟶ B[x],  add: n + m,  natural_number: $n,  int: ℤ,  equal: s = t ∈ T
Definitions unfolded in proof :  uall: ∀[x:A]. B[x],  member: t ∈ T,  uimplies: b supposing a,  double_sum: sum(f[x; y] | x < n; y < m),  all: ∀x:A. B[x],  int_seg: {i..j-},  decidable: Dec(P),  or: P ∨ Q,  implies: P ⇒ Q,  prop: ℙ,  and: P ∧ Q,  so_apply: x[s1;s2],  nat: ℕ,  subtype_rel: A ⊆r B,  so_lambda: λ2x.t[x],  so_apply: x[s],  rev_implies: P ⇐ Q,  iff: P ⇐⇒ Q,  true: True,  top: Top,  exists: ∃x:A. B[x],  satisfiable_int_formula: satisfiable_int_formula(fmla),  ge: i ≥ j ,  lelt: i ≤ j < k,  false: False,  guard: {T},  not: ¬A,  squash: ↓T,  sq_type: SQType(T)
Lemmas referenced :  decidable__equal_int,  not_wf,  equal_wf,  istype-int,  int_seg_wf,  int_subtype_base,  nat_wf,  singleton_support_sum,  sum_wf,  equal-wf-base,  set_subtype_base,  lelt_wf,  iff_weakening_equal,  subtype_rel_self,  int_formula_prop_wf,  int_formula_prop_not_lemma,  int_term_value_var_lemma,  int_formula_prop_eq_lemma,  int_formula_prop_and_lemma,  intformnot_wf,  itermVar_wf,  intformeq_wf,  intformand_wf,  full-omega-unsat,  nat_properties,  int_seg_properties,  true_wf,  squash_wf,  empty_support,  int_term_value_add_lemma,  itermAdd_wf,  member_wf,  int_formula_prop_or_lemma,  intformor_wf,  pair_support,  subtype_base_sq
Rules used in proof :  sqequalSubstitution,  sqequalTransitivity,  computationStep,  sqequalReflexivity,  Error :isect_memberFormation_alt,  introduction,  cut,  extract_by_obid,  sqequalHypSubstitution,  dependent_functionElimination,  thin,  setElimination,  rename,  because_Cache,  hypothesis,  unionElimination,  sqequalRule,  Error :functionIsType,  Error :inhabitedIsType,  hypothesisEquality,  Error :universeIsType,  isectElimination,  productEquality,  intEquality,  Error :equalityIsType4,  applyEquality,  functionExtensionality,  natural_numberEquality,  Error :isect_memberEquality_alt,  axiomEquality,  equalityTransitivity,  equalitySymmetry,  Error :unionIsType,  Error :lambdaEquality_alt,  independent_isectElimination,  Error :lambdaFormation_alt,  instantiate,  baseClosed,  imageMemberEquality,  independent_pairFormation,  voidEquality,  isect_memberEquality,  int_eqEquality,  dependent_pairFormation,  approximateComputation,  voidElimination,  productElimination,  independent_functionElimination,  universeEquality,  imageElimination,  lambdaFormation,  lambdaEquality,  dependent_set_memberEquality,  addEquality,  promote_hyp,  cumulativity

Latex:
\mforall{}[n,m:\mBbbN{}].  \mforall{}[f:\mBbbN{}n  {}\mrightarrow{}  \mBbbN{}m  {}\mrightarrow{}  \mBbbZ{}].  \mforall{}[x1,x2:\mBbbN{}n].  \mforall{}[y1,y2:\mBbbN{}m].
    (sum(f[x;y]  |  x  <  n;  y  <  m)  =  (f[x1;y1]  +  f[x2;y2]))  supposing 
          ((\mforall{}x:\mBbbN{}n.  \mforall{}y:\mBbbN{}m.    ((\mneg{}((x  =  x1)  \mwedge{}  (y  =  y1)))  {}\mRightarrow{}  (\mneg{}((x  =  x2)  \mwedge{}  (y  =  y2)))  {}\mRightarrow{}  (f[x;y]  =  0)))  and 
          ((\mneg{}(x1  =  x2))  \mvee{}  (\mneg{}(y1  =  y2))))



Date html generated: 2019_06_20-PM-02_29_38
Last ObjectModification: 2018_10_05-AM-11_03_56

Theory : num_thy_1


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