Nuprl - Proof: complete intseg mset ismin 1

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At: complete intseg mset ismin 1

1. a :

2. b :

3. f : {a..b

}

4. x :

x < b

complete_intseg_mset(a; b; f)(x) = 0

By:	Def of complete_intseg_mset(<term>; <term>; <term>) THEN Reduce Concl

Generated subgoal:

1 if a x < b f(x) else 0 fi = 0
1 step

About:

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