Nuprl - Proof: prime factorization includes prime divisors 1 2 1 1 1 2

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At: prime factorization includes prime divisors 1 2 1 1 1 2

1. a :

2. b :

3. f : {a..b

}

4. p :

5. is_prime_factorization(a; b; f)
6. prime(p)
7. p | (

i:{a..b

}. i

f(i))
8. i : {a..b

}
9. p | i

f(i)
10. f(i)

0
11. p | i
12. prime(i)
13. p = i

{a..b

} & 0<f(p)

By:	Analyze ...

Generated subgoal:

1 14. p {a..b}
0<f(p)
1 step

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html