Nuprl - Proof: hanoi extend higheq 1

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At: hanoi extend higheq 1

1. n :

2. f : {1...n}

Peg
3. n' :

4. n

n'
5. f' : {n+1...n'}

Peg
6. i : {1...n'}
7. n<i

(f {to n}

f' {to n'})(i) = f'(i)

By:	Compute (f {to n} f' {to n'})(i) * if in f(i) else f'(i) fi THEN SplitOnConclITE

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html