Nuprl - Proof: hanoi extend higheq

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At: hanoi extend higheq

, f:({1...n}

Peg), n':

(

f':({n+1...n'}

Peg), i:{1...n'}.

(n<i

(f {to n}

f' {to n'})(i) = f'(i))

By:

Auto

Generated subgoal:

1 1. n :
2. f : {1...n}Peg
3. n' :
4. nn'
5. f' : {n+1...n'}Peg
6. i : {1...n'}
7. n<i
(f {to n} f' {to n'})(i) = f'(i)
1 step

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IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html