At: min arg unique 1 2
1. f: 



2. n: 
3. k: 
4. f(n) = f(k)
5.
k < n
n-MinAr(f;n;n) = k-MinAr(f;k;k)

By: Inst
Thm*
f:(


), n:
, i:
(n+1), j:
(n-i+1).
f(n-i) = f(n) 
MinAr(f;j+i;n) = MinAr(f;j;n-i)+i
[f;k;k-n;n]
Generated subgoal:1 | f(k-(k-n)) = f(k) |
About: