Nuprl - Proof: bij imp exists inv 1 1 1 1 1

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At: bij imp exists inv 1 1 1 1 1

1. A : Type
2. B : Type
3. f : A

B
4.

a1,a2:A. f(a1) = f(a2)

a1 = a2
5. g : B

A
6.

b:B. f(g(b)) = b

InvFuns(A; B; f; g)

By:

Analyze 0

Generated subgoals:

1 g o f = Id
3 steps

2 f o g = Id
3 steps

About:

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