Nuprl - Proof: bij imp exists inv 1 1 1 1

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html
At: bij imp exists inv 1 1 1 1

1. A : Type
2. B : Type
3. f : A

B
4.

a1,a2:A. f(a1) = f(a2)

a1 = a2
5. g : B

A
6.

b:B. f(g(b)) = b

g:(B

A). InvFuns(A; B; f; g)

By:

Witness g

Generated subgoal:

1 InvFuns(A; B; f; g)
7 steps

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html