Nuprl - Proof: Ramsey-base-case 1 1 1 2 1 1

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At: Ramsey-base-case 1 1 1 2 1 1

1. L: List
2. n:
3. sum(L[i]-1 | i < ||L||)+1n
4. G: {s:(n List)| ||s|| = 1 & (x,y:||s||. x < y s[x] < s[y]) }||L||
5. p: ||L||( List)
6. sum(||p(j)|| | j < ||L||) = n
7. j:||L||, x,y:||p(j)||. x < y (p(j))[x] > (p(j))[y]
8. j:||L||, x:||p(j)||. (p(j))[x] < n & (x.G([x]))((p(j))[x]) = j
9. (c:||L||. L[c]||p(c)||)
10. i: ||L||

||p(i)||L[i]-1

By: SupposeNot

Generated subgoal:

1 11. ||p(i)||L[i]-1
||p(i)||L[i]-1 2 steps

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(30steps total) PrintForm Definitions Lemmas graph 1 2 Sections Graphs Doc