1 | 5. i:  6. i < ||filter( j.m1(1of(b),j);upto(0;size))|| 7. 2of(b) = filter( j.m1(1of(b),j);upto(0;size))[i] a:(x: size ||filter( j.m1(x,j);upto(0;size))||). (a/x,i. < x,filter( j.m1(x,j);upto(0;size))[i] > ) = b {p:( size size)| m1(1of(p),2of(p)) } | 18 steps |