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At:
append overlapping sublists1222 1. T : Type
2. L1 : T List
3. L2 : T List
4. L : T List
5. x : T 6. i,j:. i<||L|| j<||L|| i = jL[i] = L[j]
7. f1 : ||L1 @ [x]||||L||
8. increasing(f1;||L1 @ [x]||)
9. j:||L1 @ [x]||. (L1 @ [x])[j] = L[(f1(j))]
10. f : (||L2||+1)||L||
11. increasing(f;||L2||+1)
12. j:(||L2||+1). [x / L2][j] = L[(f(j))]
13. ||L1 @ [x / L2]|| = ||L1||+||L2||+1
14. ||nil||0
15. j : ||L1 @ [x / L2]||
(L1 @ [x / L2])[j] = L[if j||L1||f1(j) else f(j-||L1||) fi]
By:
AssertBY (||L1 @ [x]|| = ||L1||+1)
(RWO Thm*as,bs:T List. ||as @ bs|| = ||as||+||bs|| 0 THEN Reduce 0)
THEN
SplitOnConclITE