2 |
17. ||firstn(i+1;L) @ nth_tl(j+1;L)|| = n@0-(j-i)+1
||firstn(i+1;L) @ nth_tl(j+1;L)|| = n@0-(j-i)+1
& (firstn(i+1;L) @ nth_tl(j+1;L))[0] = x
& & last(firstn(i+1;L) @ nth_tl(j+1;L)) = y
& & ( i@0: (n@0-(j-i)).
& & ((firstn(i+1;L) @ nth_tl(j+1;L))[i@0]
& & (R (firstn(i+1;L) @ nth_tl(j+1;L))[(i@0+1)])
 | 18 steps |