Nuprl Lemma : eclass-ext
∀[T:Type]. ∀[A:es:EO+(T) ─→ E ─→ Type]. ∀[X,Y:EClass(A[es;e])].
X = Y ∈ EClass(A[es;e]) supposing ∀es:EO+(T). ∀e:E. ((X es e) = (Y es e) ∈ bag(A[es;e]))
Proof
Definitions occuring in Statement :
eclass: EClass(A[eo; e]),
event-ordering+: EO+(Info),
es-E: E,
uimplies: b supposing a,
uall: ∀[x:A]. B[x],
so_apply: x[s1;s2],
all: ∀x:A. B[x],
apply: f a,
function: x:A ─→ B[x],
universe: Type,
equal: s = t ∈ T,
bag: bag(T)
Lemmas :
bag_wf,
iff_weakening_equal,
es-E_wf,
event-ordering+_subtype,
event-ordering+_wf,
all_wf,
equal_wf
\mforall{}[T:Type]. \mforall{}[A:es:EO+(T) {}\mrightarrow{} E {}\mrightarrow{} Type]. \mforall{}[X,Y:EClass(A[es;e])].
X = Y supposing \mforall{}es:EO+(T). \mforall{}e:E. ((X es e) = (Y es e))
Date html generated:
2015_07_17-PM-00_13_46
Last ObjectModification:
2015_02_04-PM-05_37_00
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