Nuprl Lemma : fpf-compatible-join2

[A:Type]. ∀[eq:EqDecider(A)]. ∀[B:A ─→ Type]. ∀[f,g,h:a:A fp-> B[a]].  (f ⊕ || h) supposing (g || and || h)


Proof




Definitions occuring in Statement :  fpf-join: f ⊕ g fpf-compatible: || g fpf: a:A fp-> B[a] deq: EqDecider(T) uimplies: supposing a uall: [x:A]. B[x] so_apply: x[s] function: x:A ─→ B[x] universe: Type
Lemmas :  fpf-compatible-symmetry fpf-join_wf fpf-compatible-join assert_wf fpf-dom_wf top_wf subtype-fpf2 subtype_top fpf-compatible_wf fpf_wf deq_wf
\mforall{}[A:Type].  \mforall{}[eq:EqDecider(A)].  \mforall{}[B:A  {}\mrightarrow{}  Type].  \mforall{}[f,g,h:a:A  fp->  B[a]].
    (f  \moplus{}  g  ||  h)  supposing  (g  ||  h  and  f  ||  h)



Date html generated: 2015_07_17-AM-11_12_34
Last ObjectModification: 2015_01_28-AM-07_42_02

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