Nuprl Lemma : ma-ring-no-repeats-listify

R:Id List. s:{i:Id| (i  R)}   {i:Id| (i  R)} . x:Id.
  (ma-ring(R;s)  (x  R)  no_repeats(Id;(n.(s^n x))[||remove-repeats(IdDeq;R)||]))


Proof not projected




Definitions occuring in Statement :  ma-ring: ma-ring(R;s) id-deq: IdDeq Id: Id listify: listify(f;m;n) length: ||as|| all: x:A. B[x] implies: P  Q set: {x:A| B[x]}  apply: f a lambda: x.A[x] function: x:A  B[x] list: type List natural_number: $n no_repeats: no_repeats(T;l) l_member: (x  l) fun_exp: f^n remove-repeats: remove-repeats(eq;L)
Lemmas :  ma-ring-remove-repeats-eq-set-listify remove-repeats_property non_neg_length listify_length iff_wf l_eqset_wf ma-ring_wf l_contains-eq_set-no_repeats listify_wf length_wf remove-repeats_wf id-deq_wf fun_exp_wf le_wf l_member_wf int_seg_wf length_wf_nat no_repeats_wf uall_wf Id_wf nat_wf not_wf

\mforall{}R:Id  List.  \mforall{}s:\{i:Id|  (i  \mmember{}  R)\}    {}\mrightarrow{}  \{i:Id|  (i  \mmember{}  R)\}  .  \mforall{}x:Id.
    (ma-ring(R;s)  {}\mRightarrow{}  (x  \mmember{}  R)  {}\mRightarrow{}  no\_repeats(Id;(\mlambda{}n.(s\^{}n  x))[\mBbbN{}||remove-repeats(IdDeq;R)||]))


Date html generated: 2012_02_20-PM-05_58_04
Last ObjectModification: 2012_02_02-PM-02_30_08

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