Nuprl Lemma : has-value-bnot-type

[a:Base]. a ∈ Top Top supposing ba)↓


Proof




Definitions occuring in Statement :  has-value: (a)↓ bnot: ¬bb uimplies: supposing a uall: [x:A]. B[x] top: Top member: t ∈ T union: left right base: Base
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a bnot: ¬bb ifthenelse: if then else fi  has-value: (a)↓ prop:
Lemmas referenced :  base_wf has-value_wf_base
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut sqequalHypSubstitution callbyvalueDecide hypothesis equalityTransitivity equalitySymmetry sqequalRule axiomEquality lemma_by_obid isectElimination thin baseApply closedConclusion baseClosed hypothesisEquality isect_memberEquality because_Cache

Latex:
\mforall{}[a:Base].  a  \mmember{}  Top  +  Top  supposing  (\mneg{}\msubb{}a)\mdownarrow{}



Date html generated: 2016_05_13-PM-04_00_00
Last ObjectModification: 2016_01_14-PM-07_21_02

Theory : bool_1


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