Nuprl Lemma : evalall-atom1

[x:Atom1]. (evalall(x) x)


Proof




Definitions occuring in Statement :  evalall: evalall(t) atom: Atom$n uall: [x:A]. B[x] sqequal: t
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a evalall: evalall(t) has-value: (a)↓ sq_type: SQType(T) all: x:A. B[x] implies:  Q guard: {T} subtype_rel: A ⊆B or: P ∨ Q not: ¬A false: False outl: outl(x) outr: outr(x)
Lemmas referenced :  subtype_base_sq atom1_subtype_base has-value-implies-dec-ispair not-btrue-sqeq-bfalse has-value-implies-dec-isinl has-value-implies-dec-isinr
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity Error :isect_memberFormation_alt,  introduction cut thin instantiate extract_by_obid sqequalHypSubstitution isectElimination cumulativity atomnEquality independent_isectElimination hypothesis sqequalRule callbyvalueReduce callbyvalueAtom1 hypothesisEquality dependent_functionElimination equalityTransitivity equalitySymmetry independent_functionElimination axiomSqEquality Error :universeIsType,  baseApply closedConclusion baseClosed applyEquality unionElimination isAtom1ReduceTrue because_Cache voidElimination

Latex:
\mforall{}[x:Atom1].  (evalall(x)  \msim{}  x)



Date html generated: 2019_06_20-AM-11_21_03
Last ObjectModification: 2018_10_15-AM-08_52_16

Theory : call!by!value_1


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