Nuprl Lemma : has-valueall-single

[a:Base]. uiff(has-valueall(a);has-valueall([a]))


Proof




Definitions occuring in Statement :  cons: [a b] nil: [] has-valueall: has-valueall(a) uiff: uiff(P;Q) uall: [x:A]. B[x] base: Base
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uiff: uiff(P;Q) and: P ∧ Q uimplies: supposing a has-valueall: has-valueall(a) has-value: (a)↓ prop: cand: c∧ B nil: [] evalall: evalall(t) it:
Lemmas referenced :  is-exception_wf has-value_wf_base has-valueall-cons base_wf has-valueall_wf_base
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut independent_pairFormation sqequalRule sqequalHypSubstitution axiomSqleEquality hypothesis lemma_by_obid isectElimination thin hypothesisEquality baseApply closedConclusion baseClosed productElimination independent_pairEquality isect_memberEquality because_Cache equalityTransitivity equalitySymmetry independent_isectElimination divergentSqle sqleReflexivity

Latex:
\mforall{}[a:Base].  uiff(has-valueall(a);has-valueall([a]))



Date html generated: 2016_05_14-AM-06_26_08
Last ObjectModification: 2016_01_14-PM-08_26_49

Theory : list_0


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