Nuprl Lemma : last_nil

last([]) ~ ⊥


Proof




Definitions occuring in Statement :  last: last(L) nil: [] bottom: sqequal: t
Definitions unfolded in proof :  last: last(L) select: L[n] uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a all: x:A. B[x] nil: [] it: so_lambda: λ2y.t[x; y] top: Top so_apply: x[s1;s2]
Lemmas referenced :  base_wf stuck-spread
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity sqequalRule cut lemma_by_obid sqequalHypSubstitution isectElimination thin baseClosed independent_isectElimination lambdaFormation hypothesis isect_memberEquality voidElimination voidEquality

Latex:
last([])  \msim{}  \mbot{}



Date html generated: 2016_05_14-AM-06_37_30
Last ObjectModification: 2016_01_06-PM-08_33_13

Theory : list_0


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