Nuprl Lemma : has-value-last

[l:Base]. l ∈ Top × Top supposing (last(l))↓


Proof




Definitions occuring in Statement :  last: last(L) has-value: (a)↓ uimplies: supposing a uall: [x:A]. B[x] top: Top member: t ∈ T product: x:A × B[x] base: Base
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a last: last(L) select: L[n] has-value: (a)↓ prop:
Lemmas referenced :  base_wf has-value_wf_base
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut sqequalHypSubstitution sqequalRule callbyvalueSpread hypothesis equalityTransitivity equalitySymmetry axiomEquality lemma_by_obid isectElimination thin baseApply closedConclusion baseClosed hypothesisEquality isect_memberEquality because_Cache

Latex:
\mforall{}[l:Base].  l  \mmember{}  Top  \mtimes{}  Top  supposing  (last(l))\mdownarrow{}



Date html generated: 2016_05_14-AM-07_42_03
Last ObjectModification: 2016_01_15-AM-08_35_43

Theory : list_1


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