Nuprl Lemma : valueall-type-polynom

[n:ℕ]. valueall-type(polynom(n))


Proof




Definitions occuring in Statement :  polynom: polynom(n) nat: valueall-type: valueall-type(T) uall: [x:A]. B[x]
Definitions unfolded in proof :  prop: has-value: (a)↓ valueall-type: valueall-type(T) uimplies: supposing a member: t ∈ T uall: [x:A]. B[x]
Lemmas referenced :  nat_wf base_wf polynom_wf equal-wf-base valueall-type-polyform polynom_subtype_polyform polyform_wf subtype-valueall-type
Rules used in proof :  equalitySymmetry equalityTransitivity axiomSqleEquality isect_memberEquality sqequalRule independent_isectElimination hypothesis hypothesisEquality because_Cache thin isectElimination sqequalHypSubstitution extract_by_obid cut introduction isect_memberFormation sqequalReflexivity computationStep sqequalTransitivity sqequalSubstitution

Latex:
\mforall{}[n:\mBbbN{}].  valueall-type(polynom(n))



Date html generated: 2017_04_17-AM-09_03_58
Last ObjectModification: 2017_04_13-PM-01_10_45

Theory : list_1


Home Index