Nuprl Lemma : subtype_rel_functionality_wrt_implies

[A,B,C,D:Type].  ({C ⊆supposing A ⊆B}) supposing ((B ⊆D) and (A ⊇C))


Proof




Definitions occuring in Statement :  rev_subtype_rel: A ⊇B uimplies: supposing a subtype_rel: A ⊆B uall: [x:A]. B[x] guard: {T} universe: Type
Definitions unfolded in proof :  guard: {T} rev_subtype_rel: A ⊇B uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a subtype_rel: A ⊆B
Lemmas referenced :  subtype_rel_transitivity subtype_rel_wf
Rules used in proof :  sqequalSubstitution sqequalRule sqequalReflexivity sqequalTransitivity computationStep isect_memberFormation introduction cut hypothesis lemma_by_obid sqequalHypSubstitution isectElimination thin hypothesisEquality independent_isectElimination axiomEquality isect_memberEquality because_Cache equalityTransitivity equalitySymmetry universeEquality

Latex:
\mforall{}[A,B,C,D:Type].    (\{C  \msubseteq{}r  D  supposing  A  \msubseteq{}r  B\})  supposing  ((B  \msubseteq{}r  D)  and  (A  \msupseteq{}r  C))



Date html generated: 2016_05_13-PM-03_19_10
Last ObjectModification: 2015_12_26-AM-09_07_51

Theory : subtype_0


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