Nuprl Lemma : bag-union-cons

[b,a:Top].  (bag-union(a.b) bag-union(b))


Proof




Definitions occuring in Statement :  bag-union: bag-union(bbs) bag-append: as bs cons-bag: x.b uall: [x:A]. B[x] top: Top sqequal: t
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T all: x:A. B[x]
Lemmas referenced :  bag_union_cons_lemma top_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut lemma_by_obid sqequalHypSubstitution dependent_functionElimination thin hypothesisEquality hypothesis sqequalAxiom sqequalRule isect_memberEquality isectElimination because_Cache

Latex:
\mforall{}[b,a:Top].    (bag-union(a.b)  \msim{}  a  +  bag-union(b))



Date html generated: 2016_05_15-PM-02_27_44
Last ObjectModification: 2015_12_27-AM-09_51_13

Theory : bags


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