Nuprl Lemma : free-0-append
∀[X:Type]. ∀[w:free-word(X)]. (0 + w = w ∈ free-word(X))
Proof
Definitions occuring in Statement :
free-0: 0,
free-append: w + w',
free-word: free-word(X),
uall: ∀[x:A]. B[x],
universe: Type,
equal: s = t ∈ T
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
free-append: w + w',
append: as @ bs,
list_ind: list_ind,
free-0: 0,
nil: [],
it: ⋅
Lemmas referenced :
free-word_wf
Rules used in proof :
sqequalSubstitution,
sqequalTransitivity,
computationStep,
sqequalReflexivity,
isect_memberFormation,
introduction,
cut,
sqequalRule,
hypothesis,
hypothesisEquality,
extract_by_obid,
sqequalHypSubstitution,
isectElimination,
thin,
cumulativity,
isect_memberEquality,
axiomEquality,
because_Cache,
universeEquality
Latex:
\mforall{}[X:Type]. \mforall{}[w:free-word(X)]. (0 + w = w)
Date html generated:
2020_05_20-AM-08_22_25
Last ObjectModification:
2017_01_14-PM-07_29_36
Theory : free!groups
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