Nuprl Lemma : cont-induction-ext

∀[P:ℕ ⟶ ℙ]. (P[0] ⇒ (∀n:ℕ. (P[n] ⇒ P[n + 1])) ⇒ (∀n:ℕ. P[n]))


Proof




Definitions occuring in Statement :  nat: ℕ,  uall: ∀[x:A]. B[x],  prop: ℙ,  so_apply: x[s],  all: ∀x:A. B[x],  implies: P ⇒ Q,  function: x:A ⟶ B[x],  add: n + m,  natural_number: $n
Definitions unfolded in proof :  member: t ∈ T,  cont-induction,  cont-induction-lemma,  primrec-induction
Lemmas referenced :  cont-induction,  cont-induction-lemma,  primrec-induction
Rules used in proof :  introduction,  sqequalSubstitution,  sqequalTransitivity,  computationStep,  sqequalReflexivity,  cut,  instantiate,  extract_by_obid,  hypothesis,  sqequalRule,  thin,  sqequalHypSubstitution,  equalityTransitivity,  equalitySymmetry

Latex:
\mforall{}[P:\mBbbN{}  {}\mrightarrow{}  \mBbbP{}].  (P[0]  {}\mRightarrow{}  (\mforall{}n:\mBbbN{}.  (P[n]  {}\mRightarrow{}  P[n  +  1]))  {}\mRightarrow{}  (\mforall{}n:\mBbbN{}.  P[n]))



Date html generated: 2018_05_21-PM-06_59_48
Last ObjectModification: 2018_05_19-PM-04_42_03

Theory : general


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