Nuprl Lemma : isect-subtype-1
∀[F:Type ⟶ Type]. ∀[A:Type].  ((⋂A:Type. F[A]) ⊆r F[A])
Proof
Definitions occuring in Statement : 
subtype_rel: A ⊆r B
, 
uall: ∀[x:A]. B[x]
, 
so_apply: x[s]
, 
isect: ⋂x:A. B[x]
, 
function: x:A ⟶ B[x]
, 
universe: Type
Definitions unfolded in proof : 
uall: ∀[x:A]. B[x]
, 
member: t ∈ T
, 
so_apply: x[s]
, 
subtype_rel: A ⊆r B
Rules used in proof : 
sqequalSubstitution, 
sqequalTransitivity, 
computationStep, 
sqequalReflexivity, 
isect_memberFormation, 
introduction, 
cut, 
sqequalRule, 
lambdaEquality, 
isectElimination, 
hypothesisEquality, 
equalityTransitivity, 
equalitySymmetry, 
hypothesis, 
isectEquality, 
universeEquality, 
cumulativity, 
applyEquality, 
axiomEquality, 
sqequalHypSubstitution, 
isect_memberEquality, 
thin, 
because_Cache, 
functionEquality
Latex:
\mforall{}[F:Type  {}\mrightarrow{}  Type].  \mforall{}[A:Type].    ((\mcap{}A:Type.  F[A])  \msubseteq{}r  F[A])
Date html generated:
2016_05_15-PM-03_21_26
Last ObjectModification:
2015_12_27-PM-01_04_12
Theory : general
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