Nuprl Lemma : append-strict-1

[a,b:Base].  (a)↓ supposing (a b)↓


Proof




Definitions occuring in Statement :  append: as bs has-value: (a)↓ uimplies: supposing a uall: [x:A]. B[x] base: Base
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a append: as bs list_ind: list_ind has-value: (a)↓ prop:
Lemmas referenced :  base_wf has-value_wf_base
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut sqequalHypSubstitution sqequalRule callbyvalueCallbyvalue hypothesis callbyvalueReduce axiomSqleEquality lemma_by_obid isectElimination thin baseApply closedConclusion baseClosed hypothesisEquality isect_memberEquality because_Cache equalityTransitivity equalitySymmetry

Latex:
\mforall{}[a,b:Base].    (a)\mdownarrow{}  supposing  (a  @  b)\mdownarrow{}



Date html generated: 2016_05_15-PM-02_07_45
Last ObjectModification: 2016_01_15-PM-10_23_59

Theory : untyped!computation


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