Nuprl - Proof: prime factorization exists2 1 1 1 2 1 1 1

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At: prime factorization exists2 1 1 1 2 1 1 1

1. n : {1...}
2. h : {2..(n+1)

}

3. n =

{2..n+1

}(h)
4. is_prime_factorization(2; (n+1); h)
5. x : {2..(n+1)

}
6. prime(x)

h(x) = complete_intseg_mset(2; (n+1); h)(x)

By:	Rewrite by Thm* a,b:, f:({a..b}), x:{a..b}. complete_intseg_mset(a; b; f)(x) = f(x)

Generated subgoals:

None

About:

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