Nuprl - Proof: delete fenum value is fenum gen 1 2 1 1 1

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At: delete fenum value is fenum gen 1 2 1 1 1

1. P :

Prop
2. Q :

Prop
3. f : {u:

| P(u) }

{v:

| Q(v) }
4. Inj({u:

| P(u) }; {v:

| Q(v) }; f)
5. Surj({u:

| P(u) }; {v:

| Q(v) }; f)
6. m : {u:

| P(u) }
7. k : {v:

| Q(v) }
8. (Replace value k by f(m) in f)

{u:

| P(u) &

u = m }

{v:

| Q(v) &

v = k }
9. b : {v:

| Q(v) &

v = k }
10. a : {u:

| P(u) }
11. f(a) = b
12. c : {u:

| P(u) }
13. f(c) = k
14. a = m

a:{u:

| P(u) &

u = m }. (Replace value k by f(m) in f)(a) = b

By:	Analyze12 THEN Witness: c

Generated subgoal:

1 12. c :
13. P(c)
14. f(c) = k
15. a = m
(Replace value k by f(m) in f)(c) = b
2 steps

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