Nuprl - Proof: bij imp exists inv 1 1 1 1 1 1 1 1

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At: bij imp exists inv 1 1 1 1 1 1 1 1

1. A : Type
2. B : Type
3. f : A

B
4.

a1,a2:A. f(a1) = f(a2)

a1 = a2
5. g : B

A
6.

b:B. f(g(b)) = b
7. x : A

f(g(f(x))) = f(x)

By:	BackThru 6

Generated subgoals:

None

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IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html