Nuprl Lemma : blend-seq_wf

[k:ℕ+]. ∀[x,y:ℕ+ ⟶ ℤ].  (blend-seq(k;x;y) ∈ ℕ+ ⟶ ℤ)


Proof




Definitions occuring in Statement :  blend-seq: blend-seq(k;x;y) nat_plus: + uall: [x:A]. B[x] member: t ∈ T function: x:A ⟶ B[x] int:
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T blend-seq: blend-seq(k;x;y) nat_plus: +
Lemmas referenced :  ifthenelse_wf lt_int_wf nat_plus_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut sqequalRule lambdaEquality extract_by_obid sqequalHypSubstitution isectElimination thin setElimination rename hypothesisEquality hypothesis intEquality applyEquality functionExtensionality axiomEquality equalityTransitivity equalitySymmetry functionEquality isect_memberEquality because_Cache

Latex:
\mforall{}[k:\mBbbN{}\msupplus{}].  \mforall{}[x,y:\mBbbN{}\msupplus{}  {}\mrightarrow{}  \mBbbZ{}].    (blend-seq(k;x;y)  \mmember{}  \mBbbN{}\msupplus{}  {}\mrightarrow{}  \mBbbZ{})



Date html generated: 2017_10_03-AM-10_07_58
Last ObjectModification: 2017_07_05-PM-00_33_34

Theory : reals


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