Nuprl Lemma : radd-assoc
∀[x,y,z:ℝ]. ((x + y + z) = ((x + y) + z))
Proof
Definitions occuring in Statement :
req: x = y,
radd: a + b,
real: ℝ,
uall: ∀[x:A]. B[x]
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
guard: {T},
uimplies: b supposing a,
implies: P ⇒ Q
Lemmas referenced :
radd_assoc,
req_inversion,
radd_wf,
req_witness,
real_wf
Rules used in proof :
sqequalSubstitution,
sqequalTransitivity,
computationStep,
sqequalReflexivity,
isect_memberFormation,
introduction,
cut,
lemma_by_obid,
sqequalHypSubstitution,
isectElimination,
thin,
hypothesisEquality,
hypothesis,
independent_isectElimination,
independent_functionElimination,
sqequalRule,
isect_memberEquality,
because_Cache
Latex:
\mforall{}[x,y,z:\mBbbR{}]. ((x + y + z) = ((x + y) + z))
Date html generated:
2016_05_18-AM-06_51_20
Last ObjectModification:
2015_12_28-AM-00_29_36
Theory : reals
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