Nuprl Lemma : has-value-implies-dec-isatom2

t,a,b:Base.  ((t)↓  ((t ∈ Atom2) ∨ (isatom2(t;a;b) b)))


Proof




Definitions occuring in Statement :  has-value: (a)↓ atom: Atom$n isatom2: isatom2(z;a;b) all: x:A. B[x] implies:  Q or: P ∨ Q member: t ∈ T base: Base sqequal: t
Definitions unfolded in proof :  all: x:A. B[x] implies:  Q has-value: (a)↓ member: t ∈ T uall: [x:A]. B[x] or: P ∨ Q top: Top guard: {T} prop:
Lemmas referenced :  base_wf equal-wf-base top_wf is-exception_wf has-value_wf_base
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity lambdaFormation isatom2Cases divergentSqle hypothesis cut lemma_by_obid sqequalHypSubstitution isectElimination thin baseClosed hypothesisEquality sqequalRule isAtom2ReduceTrue equalityTransitivity equalitySymmetry inlFormation because_Cache sqequalIntensionalEquality isect_memberFormation introduction sqequalAxiom isect_memberEquality voidElimination voidEquality inrFormation atomnEquality

Latex:
\mforall{}t,a,b:Base.    ((t)\mdownarrow{}  {}\mRightarrow{}  ((t  \mmember{}  Atom2)  \mvee{}  (isatom2(t;a;b)  \msim{}  b)))



Date html generated: 2016_05_13-PM-03_22_56
Last ObjectModification: 2016_01_14-PM-06_46_30

Theory : call!by!value_1


Home Index