Nuprl Lemma : mk-finite-nat-seq_wf

∀[n:ℕ]. ∀[f:ℕn ⟶ ℕ].  (f^(n) ∈ finite-nat-seq())


Proof




Definitions occuring in Statement :  mk-finite-nat-seq: f^(n),  finite-nat-seq: finite-nat-seq(),  int_seg: {i..j-},  nat: ℕ,  uall: ∀[x:A]. B[x],  member: t ∈ T,  function: x:A ⟶ B[x],  natural_number: $n
Definitions unfolded in proof :  uall: ∀[x:A]. B[x],  member: t ∈ T,  mk-finite-nat-seq: f^(n),  finite-nat-seq: finite-nat-seq(),  nat: ℕ
Lemmas referenced :  nat_wf,  int_seg_wf
Rules used in proof :  sqequalSubstitution,  sqequalTransitivity,  computationStep,  sqequalReflexivity,  isect_memberFormation,  introduction,  cut,  sqequalRule,  dependent_pairEquality,  hypothesisEquality,  functionEquality,  lemma_by_obid,  sqequalHypSubstitution,  isectElimination,  thin,  natural_numberEquality,  setElimination,  rename,  hypothesis,  axiomEquality,  equalityTransitivity,  equalitySymmetry,  isect_memberEquality,  because_Cache

Latex:
\mforall{}[n:\mBbbN{}].  \mforall{}[f:\mBbbN{}n  {}\mrightarrow{}  \mBbbN{}].    (f\^{}(n)  \mmember{}  finite-nat-seq())



Date html generated: 2016_05_14-PM-09_54_32
Last ObjectModification: 2016_01_15-AM-07_44_28

Theory : continuity


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