Nuprl Lemma : subtype_rel_isect_as_subtyping_lemma
∀[A,T:Type]. ∀[B:T ⟶ Type].  A ⊆r (⋂x:T. B[x]) supposing ∀[x:T]. (A ⊆r B[x])
Proof
Definitions occuring in Statement : 
uimplies: b supposing a
, 
subtype_rel: A ⊆r B
, 
uall: ∀[x:A]. B[x]
, 
so_apply: x[s]
, 
isect: ⋂x:A. B[x]
, 
function: x:A ⟶ B[x]
, 
universe: Type
Definitions unfolded in proof : 
uall: ∀[x:A]. B[x]
, 
member: t ∈ T
, 
uimplies: b supposing a
, 
subtype_rel: A ⊆r B
, 
prop: ℙ
, 
so_lambda: λ2x.t[x]
, 
so_apply: x[s]
Lemmas referenced : 
uall_wf, 
subtype_rel_wf
Rules used in proof : 
sqequalSubstitution, 
sqequalTransitivity, 
computationStep, 
sqequalReflexivity, 
isect_memberFormation, 
introduction, 
cut, 
lambdaEquality, 
isect_memberEquality, 
hypothesisEquality, 
applyEquality, 
hypothesis, 
sqequalHypSubstitution, 
isectElimination, 
thin, 
sqequalRule, 
axiomEquality, 
lemma_by_obid, 
because_Cache, 
equalityTransitivity, 
equalitySymmetry, 
functionEquality, 
cumulativity, 
universeEquality
Latex:
\mforall{}[A,T:Type].  \mforall{}[B:T  {}\mrightarrow{}  Type].    A  \msubseteq{}r  (\mcap{}x:T.  B[x])  supposing  \mforall{}[x:T].  (A  \msubseteq{}r  B[x])
Date html generated:
2016_05_13-PM-03_18_53
Last ObjectModification:
2015_12_26-AM-09_08_07
Theory : subtype_0
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