Nuprl Lemma : eq_int_eq_false_elim_sqequal

[i,j:ℤ].  i ≠ supposing (i =z j) ff


Proof




Definitions occuring in Statement :  eq_int: (i =z j) bfalse: ff uimplies: supposing a uall: [x:A]. B[x] nequal: a ≠ b ∈  int: sqequal: t
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a nequal: a ≠ b ∈  not: ¬A implies:  Q false: False uiff: uiff(P;Q) and: P ∧ Q prop: subtype_rel: A ⊆B
Lemmas referenced :  assert_of_ff neg_assert_of_eq_int equal-wf-base int_subtype_base
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut lambdaFormation thin sqequalRule hypothesis extract_by_obid sqequalHypSubstitution isectElimination hypothesisEquality productElimination independent_isectElimination independent_functionElimination voidElimination intEquality applyEquality lambdaEquality dependent_functionElimination because_Cache sqequalIntensionalEquality baseApply closedConclusion baseClosed isect_memberEquality equalityTransitivity equalitySymmetry

Latex:
\mforall{}[i,j:\mBbbZ{}].    i  \mneq{}  j  supposing  (i  =\msubz{}  j)  \msim{}  ff



Date html generated: 2017_04_14-AM-07_36_36
Last ObjectModification: 2017_02_27-PM-03_08_43

Theory : subtype_1


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