Nuprl Lemma : fpf-trivial-subtype-top

[A:Type]. ∀[B:A ⟶ Type]. ∀[f:a:A fp-> B[a]].  (f ∈ a:A fp-> Top)


Proof




Definitions occuring in Statement :  fpf: a:A fp-> B[a] uall: [x:A]. B[x] top: Top so_apply: x[s] member: t ∈ T function: x:A ⟶ B[x] universe: Type
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T subtype_rel: A ⊆B so_lambda: λ2x.t[x] so_apply: x[s] uimplies: supposing a all: x:A. B[x] top: Top
Lemmas referenced :  subtype-fpf2 top_wf fpf_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut hypothesisEquality applyEquality lemma_by_obid sqequalHypSubstitution isectElimination thin sqequalRule lambdaEquality hypothesis independent_isectElimination lambdaFormation isect_memberEquality voidElimination voidEquality because_Cache axiomEquality equalityTransitivity equalitySymmetry functionEquality cumulativity universeEquality

Latex:
\mforall{}[A:Type].  \mforall{}[B:A  {}\mrightarrow{}  Type].  \mforall{}[f:a:A  fp->  B[a]].    (f  \mmember{}  a:A  fp->  Top)



Date html generated: 2018_05_21-PM-09_17_25
Last ObjectModification: 2018_02_09-AM-10_16_31

Theory : finite!partial!functions


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