Nuprl Lemma : iteration_terminates

∀[T:Type]
  ∀f:T ⟶ T. ∀m:T ⟶ ℕ.
    ∀x:T. ∃n:ℕ. ((f (f^n x)) = (f^n x) ∈ T) 
    supposing ∀x:T. (((m (f x)) ≤ (m x)) ∧ (f x) = x ∈ T supposing (m (f x)) = (m x) ∈ ℤ)


Proof




Definitions occuring in Statement :  fun_exp: f^n,  nat: ℕ,  uimplies: b supposing a,  uall: ∀[x:A]. B[x],  le: A ≤ B,  all: ∀x:A. B[x],  exists: ∃x:A. B[x],  and: P ∧ Q,  apply: f a,  function: x:A ⟶ B[x],  int: ℤ,  universe: Type,  equal: s = t ∈ T
Definitions unfolded in proof :  uall: ∀[x:A]. B[x],  all: ∀x:A. B[x],  uimplies: b supposing a,  member: t ∈ T,  and: P ∧ Q,  le: A ≤ B,  subtype_rel: A ⊆r B,  nat: ℕ,  so_lambda: λ2x.t[x],  so_apply: x[s],  top: Top,  decidable: Dec(P),  or: P ∨ Q,  iff: P ⇐⇒ Q,  not: ¬A,  rev_implies: P ⇐ Q,  implies: P ⇒ Q,  false: False,  uiff: uiff(P;Q),  subtract: n - m,  less_than': less_than'(a;b),  true: True,  nat_plus: ℕ+,  prop: ℙ,  guard: {T},  squash: ↓T,  exists: ∃x:A. B[x],  sq_stable: SqStable(P),  ge: i ≥ j ,  less_than: a < b
Lemmas referenced :  le_witness_for_triv,  istype-le,  istype-nat,  istype-int,  set_subtype_base,  le_wf,  int_subtype_base,  istype-universe,  fun_exp0_lemma,  istype-void,  decidable__le,  subtract_wf,  istype-false,  not-le-2,  condition-implies-le,  minus-add,  minus-one-mul,  add-swap,  minus-one-mul-top,  add-mul-special,  zero-mul,  add-zero,  minus-zero,  add-associates,  zero-add,  add-commutes,  le-add-cancel,  fun_exp_wf,  less-iff-le,  minus-minus,  add_functionality_wrt_le,  istype-less_than,  primrec-wf2,  or_wf,  equal_wf,  fun_exp_add1_sub,  equal-wf-base,  decidable__lt,  le_weakening2,  le-add-cancel2,  decidable__int_equal,  not-equal-2,  not-lt-2,  squash_wf,  true_wf,  subtype_rel_self,  iff_weakening_equal,  fun_exp_add,  istype_wf,  add_nat_wf,  sq_stable__le,  istype-sqequal,  nat_properties,  le-add-cancel-alt,  le_reflexive,  one-mul,  two-mul,  mul-distributes-right,  omega-shadow
Rules used in proof :  sqequalSubstitution,  sqequalTransitivity,  computationStep,  sqequalReflexivity,  Error :isect_memberFormation_alt,  Error :lambdaFormation_alt,  cut,  introduction,  sqequalRule,  sqequalHypSubstitution,  Error :lambdaEquality_alt,  dependent_functionElimination,  thin,  hypothesisEquality,  productElimination,  independent_pairEquality,  extract_by_obid,  isectElimination,  equalityTransitivity,  hypothesis,  equalitySymmetry,  independent_isectElimination,  Error :isect_memberEquality_alt,  axiomEquality,  Error :isectIsTypeImplies,  Error :inhabitedIsType,  Error :functionIsTypeImplies,  rename,  Error :universeIsType,  Error :functionIsType,  Error :productIsType,  applyEquality,  setElimination,  because_Cache,  Error :isectIsType,  Error :equalityIstype,  intEquality,  closedConclusion,  natural_numberEquality,  sqequalBase,  instantiate,  universeEquality,  voidElimination,  unionElimination,  Error :inlFormation_alt,  independent_pairFormation,  addEquality,  minusEquality,  multiplyEquality,  independent_functionElimination,  Error :inrFormation_alt,  Error :unionIsType,  Error :dependent_set_memberEquality_alt,  Error :setIsType,  hyp_replacement,  applyLambdaEquality,  productEquality,  isectEquality,  Error :equalityIsType1,  imageElimination,  imageMemberEquality,  baseClosed,  unionEquality,  Error :dependent_pairFormation_alt,  promote_hyp

Latex:
\mforall{}[T:Type]
    \mforall{}f:T  {}\mrightarrow{}  T.  \mforall{}m:T  {}\mrightarrow{}  \mBbbN{}.
        \mforall{}x:T.  \mexists{}n:\mBbbN{}.  ((f  (f\^{}n  x))  =  (f\^{}n  x)) 
        supposing  \mforall{}x:T.  (((m  (f  x))  \mleq{}  (m  x))  \mwedge{}  (f  x)  =  x  supposing  (m  (f  x))  =  (m  x))



Date html generated: 2019_06_20-PM-00_27_05
Last ObjectModification: 2018_11_23-PM-00_41_17

Theory : fun_1


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