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At: prime factorization exists 1 2 1 1

1. n : {1...}
2. g : {2..(n+1)}
3. n = {2..n+1}(g)
4. h:({2..(n+1)}). 
4. {2..n+1}(g) = {2..n+1}(h) & is_prime_factorization(2; (n+1); h)
  h:({2..(n+1)}). n = {2..n+1}(h) & is_prime_factorization(2; (n+1); h)


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intnatural_numberaddfunctionequalandexists
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(8steps total) PrintForm Definitions Lemmas FTA Sections DiscrMathExt Doc