Nuprl Lemma : has-value-band

[a,b:Base].  (a)↓ supposing (a ∧b b)↓


Proof




Definitions occuring in Statement :  band: p ∧b q has-value: (a)↓ uimplies: supposing a uall: [x:A]. B[x] base: Base
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a band: p ∧b q ifthenelse: if then else fi  has-value: (a)↓ prop:
Lemmas referenced :  base_wf has-value_wf_base top_wf union-value-type value-type-has-value
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut sqequalHypSubstitution callbyvalueDecide hypothesis lemma_by_obid isectElimination thin because_Cache independent_isectElimination sqequalRule axiomSqleEquality baseApply closedConclusion baseClosed hypothesisEquality isect_memberEquality equalityTransitivity equalitySymmetry

Latex:
\mforall{}[a,b:Base].    (a)\mdownarrow{}  supposing  (a  \mwedge{}\msubb{}  b)\mdownarrow{}



Date html generated: 2016_05_13-PM-03_59_48
Last ObjectModification: 2016_01_14-PM-07_20_58

Theory : bool_1


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