Nuprl Lemma : is_int_wf

[T:Type]. ∀[x:T]. (is_int(x) ∈ 𝔹supposing value-type(T) ∧ (T ⊆Base)


Proof




Definitions occuring in Statement :  is_int: is_int(x) value-type: value-type(T) bool: 𝔹 uimplies: supposing a subtype_rel: A ⊆B uall: [x:A]. B[x] and: P ∧ Q member: t ∈ T base: Base universe: Type
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a is_int: is_int(x) and: P ∧ Q has-value: (a)↓ subtype_rel: A ⊆B top: Top
Lemmas referenced :  value-type-has-value has-value_wf_base is-exception_wf btrue_wf istype-top istype-void bfalse_wf value-type_wf subtype_rel_wf base_wf istype-universe
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity Error :isect_memberFormation_alt,  introduction cut sqequalRule sqequalHypSubstitution productElimination thin callbyvalueReduce extract_by_obid isectElimination hypothesisEquality independent_isectElimination hypothesis isintCases divergentSqle because_Cache baseClosed applyEquality isintReduceTrue equalityTransitivity equalitySymmetry axiomSqEquality Error :inhabitedIsType,  Error :isect_memberEquality_alt,  Error :isectIsTypeImplies,  voidElimination axiomEquality Error :universeIsType,  Error :productIsType,  instantiate universeEquality

Latex:
\mforall{}[T:Type].  \mforall{}[x:T].  (is\_int(x)  \mmember{}  \mBbbB{})  supposing  value-type(T)  \mwedge{}  (T  \msubseteq{}r  Base)



Date html generated: 2019_06_20-AM-11_33_08
Last ObjectModification: 2019_02_07-AM-11_53_28

Theory : int_1


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